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Re: [課業]輸配電學~傳播常數開根號問題?
Oct 27th 2014, 22:49, by light503

作者light503 (笑面男)

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標題Re: [課業]輸配電學~傳播常數開根號問題?

時間Mon Oct 27 22:49:38 2014

※ 引述《bluert (WW)》之銘言: : 題目︰某三相60Hz之輸電線,串聯阻抗z=0.524∠79.04度 Ω/km : 並聯導納y=j0.000003728 S/km,求傳播常數? : γ=√yz : =√(j0.000003728)×(0.524∠79.04度) : =0.00012313+j0.0012835 : 我想請教教複數如何根號呢? : 謝謝 倘若並聯導納y=j0.0000031728 S/km,進行計算 γ=√yz =√(j0.0000031728)×(0.524∠79.04度) =√{(0.0000031728∠90)×(0.524∠79.04)} =√{1.662547*10-6∠169.04} =1.2894*10-3∠84.52 (註:169.04/2=84.52) =0.00012313+j0.0012835 (註:將極座標化為直角坐標) 希望有解出你心中的疑惑,我也是今年國營的考生。 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 118.170.57.127 ※ 文章網址: http://www.ptt.cc/bbs/Examination/M.1414421381.A.BC0.html

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