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一.Y=C+I+G+X-M=100+0.75Yd+60+60+100-(60+0.15Yd)=260+0.6(Y-60)

求均衡所得水準為何?

Y=224+0.6Y，0.4Y=224，故Y*=560
Y=C+I+G+NX

一式中0.75+0.2=1;0.6+0.4=1
請問0.6是如何求解,帶公式嗎?
224+0.6Y
0.4Y=224

題目沒告知T=60，其餘只是數學運算
Y=C+I+G+X-M=100+0.75Yd+60+60+100-(60+0.15Yd)
=(100+60+60+100-60)+(0.75Yd-0.15Yd)=260+0.6Yd
題目沒告知T=60，若沒錯，可支配所得Yd=Y-T=Y-60
所以Y=260+0.6(Y-60)=260+0.6Y-36=224+0.6Y，Y-0.6Y=224，0.4Y=224，Y*=560

二.Y= 100+0.75(Y-20-0.05Y)+20+0.1Y+80+(120-30-0.5Y)=275+0.3125Y
0.6875Y=275
二式中0.75+0.2=1;0.3125+0.6875=1
請問0.3125是如何求解,帶公式嗎?
275+0.3125Y
0.6875Y=275

Y= 100+0.75(Y-20-0.05Y)+20+0.1Y+80+(120-30-0.5Y)
Y=100+0.75(0.95Y-20)+20+0.1Y+80+(120-30-0.5Y)
Y=100+0.7125Y-15+20+0.1Y+80+120-30-0.5Y
Y=(100-15+20+80+120-30)+(0.7125Y+0.1Y-0.5Y)
Y=275+0.3125Y，Y-0.3125Y=275，0.6875Y=275，Y*=400
如果題目條件給的沒錯，代入Y=C+I+G+X-M，Yd=Y-T，其餘只是數學運算

參考資料 小小淺見

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